What the animation shows
The animation and the step-by-step video above use your numbers. Here is the same walkthrough written out for the default example.

What you enter
- Conductor material: Copper.
- Conductor size: 12 AWG.
- One-way circuit length: 100 ft. Distance from the panel to the load, not the round trip.
- Load current: 20 A.
- Voltage: 120 V.
- System: Single-phase (or DC).
What happens, step by step
- Load on: 20 A flows out on one wire and back on the other.
- The 12 AWG copper resists the current, so voltage falls along all 100 ft.
- 112.1 V reaches the load: 7.9 V lost, a 6.59% drop.
- Over the 3% guideline: use a larger wire or a shorter run.
The answer: voltage drop is 6.59%.
How it’s calculated
- Single-phase: VD = 2 × K × I × L ÷ cmil
- Three-phase: VD = √3 × K × I × L ÷ cmil
- K = 12.9 (copper) or 21.2 (aluminum) Ω·cmil/ft at about 75 °C
- cmil from the AWG definition: d = 0.005 × 92^((36 − n) ÷ 39) in
Worked example
12 AWG copper, 100 ft one way, 20 A at 120 V single-phase.
Inputs
- Conductor material
- Copper
- Conductor size
- 12 AWG
- One-way circuit length
- 100 ft
- Load current
- 20 A
- Voltage
- 120 V
- System
- Single-phase (or DC)
Results
- Voltage drop
- 6.59%
- Voltage drop
- 7.9 V
- Voltage at the load
- 112.1 V
- Conductor area
- 6,530 cmil
Assumptions and limits
- DC resistance method; reactance is ignored (acceptable for small conductors at 60 Hz).
- Conductor temperature near 75 °C.
Verify the result against the applicable local code, adopted code edition, manufacturer instructions and project requirements. See our methodology.
Questions
What is an acceptable voltage drop?
The NEC suggests (in informational notes) 3% for a branch circuit and 5% for feeder plus branch combined.
Does voltage drop depend on the breaker?
No — it depends on the actual current, conductor size, material and length.